Răspuns:
[tex]f) x=3\\\\g) x=-\frac{128}{5} \\\\h) x=-\frac{13}{43}[/tex]
Explicaţie pas cu pas:
|__________Δ×Δ×Δ×Δ×Δ×Δ__________|
Bună!
[tex]f) 5(3-2x)-3x-2-6(2x-3) = 2(3-4x)-2(3x+4)\\ 5(-2x+3)-3x-2+6(2x-3)= 2(-4+3)-2(3x+4)\\5(-2x+3)-3x-2+6(2x+3)=(-2*4x+2*3)-(2*3x+2*4)\\5(-2x+3)+6(-2x+3)-3x-2=(-8x+6)-(6x+8)\\11(-2x+3)-3x-2=-8x+6x+6-8\\(-11*2x+11*3)-3x-2=-8x-6x+6-8\\(-22x+33)-3x-2=-14x-2\\-22x+33-3x-2=-14x-2\\-22x-3x+33-2=-14x-2\\-25x+31=-14x-2\\(25x+31)+(-31+14x)=(-14x-2)+(-31+14x)\\(25x+31)+(14x-31)=(-14x-2)+(14x-31)\\-25x+31+14x-31=-14x-2+14x-31\\-25x+14x+31-31=-14x+14x-2-31\\-11x=-33/:11\\-11x=33/11\\x=3[/tex]
[tex]g)4(9x-4)-2(7x-2x)-7x=5(x-22)-3(10-3x)-4\\\4(9x-4)-2(5x)-7x= 5(x-22)-3(3x+10)+4\\4(9x-4)-2*5x-7x=(5x-5*22)-(-3*3x+3*10)-4\\4(9x-4)-10x-7x=(5x-110)-(-9x+30)-4\\4(9x-4)-17x=5x-110+9x-30-4\\(4*9x-4*4)-17x=5x+9x-110-30-4\\(36x-16)-17x=14x-114\\36x-16-17x=14x-114\\36x-17x-16=14x-114\\19x-16=14x-114\\(19x-16)+(16-14x)=(14x-114)+(16-14x)\\(19x-16)+(-14x+16)=(14x-114)+(-14x+16)\\19x-16-14x+16=14x-114-14x+16\\19x-14x-16+16=14x-14x-114+16\\5x=-128/:5\\\\x=-\frac{128}{5}[/tex]
[tex]h)2(5x-4)-(3x+2)-3(5x-10)=3x-6(4x-3)-11\\2(5x-4)-3x-2+3(5x+10)=3x-(6*4x-6*3)-11\\2(5x-4)-3x+3(5x+10)-2=3x-(24x-18)-11\\..............\\x=-\frac{13}{43}[/tex]
Pe acesta, îl vei rezolva singur/singură după cele două modele de la subpunctele anterioare.
#Mult succes şi mult spor!
SandyBell23
