Răspuns: 5 → Varianta b)
Explicație pas cu pas:
[tex]\bf a = \sqrt{6}[/tex]
[tex]\bf b = \sqrt{3} -\sqrt{2}[/tex]
[tex]\bf b^{2}+2a =\Big(\sqrt{3} -\sqrt{2}\Big)^{2}+2\sqrt{6} =\Big(\sqrt{3}\Big)^{2}-2\sqrt{3}\cdot\sqrt{2} +\Big(\sqrt{2}\Big)^{2}+2\sqrt{6} =[/tex]
[tex]\bf 3-2\sqrt{6}+2+2\sqrt{6} =5-2\sqrt{6}+2\sqrt{6} =\red{\underline{~5~}}[/tex]
